serq - execute functions serially

This project is inspired by seq-queue.

USAGE

BASICS

let queue = new Serq()

queue.push(async () => {
  await new Promise(r => { setTimeout(r, 100) })
  console.log('func 0')
})

queue.push(() => {
  console.log('func 1')
})

// output:
//
// func 0
// func 1

Return values

let queue = new Serq()
let ret = queue.push(() => {
  return 'value'
})

console.log(await ret)

// output:
//
// value

Errors

let queue = new Serq()
queue.push(() => {
  throw new Error('an error')
})
.catch(err) {
  console.log('error: ', err.message)
}

// output:
//
// an error

Timeouts

When timeout happens, Serq executes the function next in queue.

let queue = new Serq(500) // default timeout is 3000

queue.push(async () => {
  await new Promise(r => { setTimeout(r, 1000) })
  console.log('task 0 done')
}, {
  ontimeout: () => {
    console.log('timeout')
}
})

queue.push(() => {
  console.log('task 1 done')
})

// output:
//
// timeout
// task 1 done
// task 0 done

LICENSE

MIT