怎么在不修改代码的情况下设置so导出符号 #4959
Replies: 4 comments 6 replies
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另外有没有只导出其中一个链接库的符号的，比如libA.so链接了现成的libB.so， |
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默认情况下，so 就是 default visibility ，也就是默认就是全部符号导出的，不需要任何配置。。 xmake 的配置，如果你配置了
肯定有效果，我不知道你说的没效果是啥，
建议你先了解下 so 的基础概念, 别把 so 和 静态库搞混了，A.so 不可能导出 B.so 的 |
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不好意思问错了，B是 .a 是配置了 |
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先确认下 debug mode 是否会导出，或者移除 mode.release rules |
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另外提的导出 .a 的符号找到解决方案 |
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既然 debug 可以，那不就是 set_symbols/set_strip 的问题么，你自己配下就行了。。 自己对比下 xmake/xmake/rules/mode/xmake.lua Line 49 in 7e7b37e
不要去对比这个，没啥意义，xmake 的 release 要尽可能小，符号导出都是建议自己代码里面自己导出的，这样生成的 so 能尽可能最小最优，而不是默认一股脑全导出。。 当然，你也可以不用内置的 mode.release 。。。自己配 mode |
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另外，对于 so ，目前 release mode 默认就是会导出的。。 xmake/xmake/rules/mode/xmake.lua Line 48 in 7e7b37e 你这里不行，我估计你根本没说清楚你这里的配置，我猜你是 shared target 去 link 了一个 static target，而你的导出符号是在这个 static target 里，而不是 so 所在的 target。。 这种情况，你得对这个 static target 去 set_symbols none，而不是对 shared target，否则肯定不生效。。符号在哪个 target ，就对哪个 target 配置 |
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但是我这编出来就是啥都没有耶，纯的qt.shared $ nm build/linux/x86_64/release/libtest.so
nm: build/linux/x86_64/release/libtest.so: no symbols$ xmake build -rvD
[ 50%]: cache compiling.release src/demo.cpp
/usr/bin/gcc -c -m64 -O3 -std=c++11 -I/home/administrator/test/build/.gens/test/linux/x86_64/release/rules/qt/ui -DQT_DEMO_LIBRARY -DQT_NO_DEBUG -DQT_DEPRECATED_WARNINGS -DQT_GUI_LIB -DQT_CORE_LIB -isystem /home/administrator/Qt5.14.2/5.14.2/gcc_64/include/QtGui -isystem /home/administrator/Qt5.14.2/5.14.2/gcc_64/include/QtGui/5.14.2 -isystem /home/administrator/Qt5.14.2/5.14.2/gcc_64/include/QtGui/5.14.2/QtGui -isystem /home/administrator/Qt5.14.2/5.14.2/gcc_64/include/QtCore -isystem /home/administrator/Qt5.14.2/5.14.2/gcc_64/include/QtCore/5.14.2 -isystem /home/administrator/Qt5.14.2/5.14.2/gcc_64/include/QtCore/5.14.2/QtCore -isystem /home/administrator/Qt5.14.2/5.14.2/gcc_64/include -isystem /home/administrator/Qt5.14.2/5.14.2/gcc_64/mkspecs/linux-g++ -DNDEBUG -fPIC -o build/.objs/test/linux/x86_64/release/src/demo.cpp.o src/demo.cpp
[ 75%]: linking.release libtest.so
/usr/bin/g++ -o build/linux/x86_64/release/libtest.so build/.objs/test/linux/x86_64/release/src/demo.cpp.o -shared -m64 -fPIC -L/home/administrator/Qt5.14.2/5.14.2/gcc_64/lib -Wl,-rpath=/home/administrator/Qt5.14.2/5.14.2/gcc_64/lib -s -lQt5Gui -lQt5Core
build cache stats:
cache directory: build/.build_cache
cache hit rate: 100%
cache hit: 1
cache hit total time: 0.000s
cache miss: 0
cache miss total time: 0.000s
new cached files: 0
remote cache hit: 0
remote new cached files: 0
preprocess failed: 0
compile fallback count: 0
compile total time: 0.000s
[100%]: build ok, spent 0.275s |
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不是有的么，哪不行了？ $ nm -D build/linux/x86_64/release/libtest.so
w _ITM_deregisterTMCloneTable
w _ITM_registerTMCloneTable
0000000000001110 T _Z1fv
0000000000001100 T _ZN6QtDemoC1Ev
0000000000001100 T _ZN6QtDemoC2Ev
w __cxa_finalize
w __gmon_start__
U qt_version_tag@Qt_5.15 |
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好吧，好像是可以，不知道要加-D |
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release下试了
set_symbols("debug")、set_symbols("none")、add_rules("utils.symbols.export_list")都没效果，都是只有额外的sym能导出符号，但是我希望是so本身有Beta Was this translation helpful? Give feedback.
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