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ex15.23.cpp
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ex15.23.cpp
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/***************************************************************************
* @file main.cpp
* @author Alan.W
* @date 24 Jan 2014
* @remark This code is for the exercises from C++ Primer 5th Edition
* @note
***************************************************************************/
//
// Exercise 15.23:
// Assuming class D1 on page 620 had intended to override its inherited fcn
// function, how would you fix that class? Assuming you fixed the class so
// that fcn matched the definition in Base, how would the calls in that section
// be resolved?
// remove the parameter int.
// Disscussion on SO :
// http://stackoverflow.com/questions/21320779/trying-to-understand-dynamic-binding-and-virtual-functions
#include <iostream>
#include <string>
class Base
{
public:
virtual int fcn(){ std::cout << "Base::fcn()\n"; return 0; }
};
class D1 : public Base
{
public:
int fcn() override { std::cout << "D1::fcn()\n";return 0; }
// ^^^--fixed to override the inherited version
virtual void f2() { std::cout << "D1::f2()\n"; }
};
class D2 : public D1
{
public:
int fcn(int);
int fcn() override { std::cout << "D2::fcn()\n";return 0; }
void f2() override { std::cout << "D2::f2()\n"; }
};
int main()
{
Base bobj;
D1 d1obj;
D2 d2obj;
Base *bp1 = &bobj, *bp2 = &d1obj, *bp3 = &d2obj;
//bp1->fcn(); // virtual call, will call Base::fcn at run time
//bp2->fcn(); // virtual call, will call D1::fcn at run time
//bp3->fcn(); // virtual call, will call D2::fcn at run time
D1 *d1p = &d1obj; D2 *d2p = &d2obj;
//bp2->f2();
//^^^^^^^^^^^^
// @note You are calling virtual member functions via a pointer
// to Base. That means that you can only call methods that exist
// in the Base class. You cannot simply add methods to a type
// dynamically.
//d1p->f2(); // virtual call, will call D1::f2() at run time
//d2p->f2(); // virtual call, will call D2::f2() at run time
return 0;
}