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hw01.py
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from operator import add, sub
def a_plus_abs_b(a, b):
"""Return a+abs(b), but without calling abs.
>>> a_plus_abs_b(2, 3)
5
>>> a_plus_abs_b(2, -3)
5
"""
if b < 0:
f = a-b
else:
f = a+b
return f(a, b)
def a_plus_abs_b_syntax_check():
"""Check that you didn't change the return statement of a_plus_abs_b.
>>> # You aren't expected to understand the code of this test.
>>> import inspect, re
>>> re.findall(r'^\s*(return .*)', inspect.getsource(a_plus_abs_b), re.M)
['return f(a, b)']
"""
# You don't need to edit this function. It's just here to check your work.
def two_of_three(x, y, z):
"""Return a*a + b*b, where a and b are the two smallest members of the
positive numbers x, y, and z.
>>> two_of_three(1, 2, 3)
5
>>> two_of_three(5, 3, 1)
10
>>> two_of_three(10, 2, 8)
68
>>> two_of_three(5, 5, 5)
50
"""
return x*x+y*y+z*z-max(x,y,z)**2
def two_of_three_syntax_check():
"""Check that your two_of_three code consists of nothing but a return statement.
>>> # You aren't expected to understand the code of this test.
>>> import inspect, ast
>>> [type(x).__name__ for x in ast.parse(inspect.getsource(two_of_three)).body[0].body]
['Expr', 'Return']
"""
# You don't need to edit this function. It's just here to check your work.
def largest_factor(n):
"""Return the largest factor of n that is smaller than n.
>>> largest_factor(15) # factors are 1, 3, 5
5
>>> largest_factor(80) # factors are 1, 2, 4, 5, 8, 10, 16, 20, 40
40
>>> largest_factor(13) # factor is 1 since 13 is prime
1
"""
if n%2==0:
return n/2
elif n%3==0:
return n/3
elif n%5==0 :
return n/5
else:
return 1
def limited(x, z, limit):
"""Logic that is common to invert and change."""
if x != 0:
return min(z, limit)
else:
return limit
def invert_short(x, limit):
"""Return 1/x, but with a limit.
>>> x = 0.2
>>> 1/x
5.0
>>> invert_short(x, 100)
5.0
>>> invert_short(x, 2) # 2 is smaller than 5
2
>>> x = 0
>>> invert_short(x, 100) # No error, even though 1/x divides by 0!
100
"""
return limited(x, 1 / x, limit)
def change_short(x, y, limit):
"""Return abs(y - x) as a fraction of x, but with a limit.
>>> x, y = 2, 5
>>> abs(y - x) / x
1.5
>>> change_short(x, y, 100)
1.5
>>> change_short(x, y, 1) # 1 is smaller than 1.5
1
>>> x = 0
>>> change_short(x, y, 100) # No error, even though abs(y - x) / x divides by 0!
100
"""
return limited(x, abs(y - x) / x, limit)
def invert_and_change_syntax_check():
"""Checks that definitions of invert_short and change_short are just return statements.
>>> # You aren't expected to understand the code of this test.
>>> import inspect, ast
>>> [type(x).__name__ for x in ast.parse(inspect.getsource(invert_short)).body[0].body]
['Expr', 'Return']
>>> [type(x).__name__ for x in ast.parse(inspect.getsource(change_short)).body[0].body]
['Expr', 'Return']
"""
# You don't need to edit this function. It's just here to check your work.
def hailstone(n):
"""Print the hailstone sequence starting at n and return its
length.
>>> a = hailstone(10)
10
5
16
8
4
2
1
>>> a
7
"""
while n!=1:
print(n)
if n%2==0:
n=n//2
elif n%2==1:
n=n*3+1
print(1)
"*** YOUR CODE HERE ***"
quine = ''
def quine_test():
"""
>>> quine_test()
QUINE!
"""
import contextlib, io
f = io.StringIO()
with contextlib.redirect_stdout(f):
exec(quine)
quine_output = f.getvalue()
if quine == quine_output:
print("QUINE!")
return
print("Not a quine :(")
print("Code was: %r" % quine)
print("Output was: %r" % quine_output)
print("Side by side:")
print(quine)
print("*" * 100)
print(quine_output)
print("*" * 100)