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pandas.DataFrame() is Any #292

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JelleZijlstra opened this issue Dec 2, 2021 · 0 comments

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JelleZijlstra commented Dec 2, 2021

Revealed type is 'Any[from_another]' (code: inference_failure)
In <test input> at line 6
   3: def f() -> pandas.DataFrame():  # E: invalid_annotation
   4:     reveal_type(f)
   5:     reveal_type(pandas.DataFrame)
   6:     reveal_type(pandas.DataFrame())
                      ^
   7:     raise NotImplementedError

(found while I was trying to figure out why the annotation wasn't flagged as invalid—perhaps we should be stricter there anyway)

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