v2.10.3 get_user_info 使用 uid 无法查询

[single-ptilopsis]

如何复现

test.py

import asyncio

import aiotieba as tb


async def run():
    async with tb.Client() as client:
        user = await client.get_user_info(809141539)
        print(user)
        print(user.user_id)


loop = asyncio.get_event_loop()
loop.run_until_complete(run())

aiotieba.toml

[User]

# default是自定义的BDUSS_key，你可以改成你喜欢的标识
# 该设计是为了方便通过BDUSS_key快速调用BDUSS，这样你就不用每次都填一串很长的东西作为参数
[User.default]
BDUSS = "" # 把你的那一串长长的BDUSS放在这

python 3.9 v2.10.3

<2023-01-13 15:30:51.254> [WARN] [_get_uinfo_getUserInfo] (110000, '请先登录'). user=809141539
<2023-01-13 15:30:51.254> [WARN] [get_user_info] Null input
0
0

python 3.9 v2.9.1

雪景suki
809141539

你希望程序作出何种行为
如 v2.9.1 所示

[n0099]

https://github.com/Starry-OvO/aiotieba/blob/27f125a3c2e18bc581ccbf7b8b4d6cffdb19e739/aiotieba/client/__init__.py#L523
https://github.com/Starry-OvO/aiotieba/blob/27f125a3c2e18bc581ccbf7b8b4d6cffdb19e739/aiotieba/client/__init__.py#L605

possible related #77

[lumina37]

这玩意就是要有BDUSS才能用的啊

import asyncio

import aiotieba as tb


async def run():
    async with tb.Client('default') as client:
        user = await client._get_uinfo_getUserInfo(809141539)
        print(user)
        print(user.user_id)


asyncio.run(run())

输出

雪景suki
809141539

[single-ptilopsis]

看了下请求代码，加上 require=tb.ReqUInfo.OTHER 请求的接口便和 v2.9.1一致，不需要BDUSS

import asyncio

import aiotieba as tb


async def run():
    async with tb.Client() as client:
        user = await client.get_user_info(809141539,require=tb.ReqUInfo.OTHER)
        print(user)
        print(user.user_id)


loop = asyncio.get_event_loop()
loop.run_until_complete(run())