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102.binary-tree-level-order-traversal.py
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from lc import *
class Solution:
def levelOrder(self, root: TreeNode) -> List[List[int]]:
res = []
q = deque()
if root:
q.append(root)
while q:
level = []
for _ in range(len(q)):
root = q.popleft()
level.append(root.val)
if root.left:
q.append(root.left)
if root.right:
q.append(root.right)
res.append(level)
return res
class Solution:
def levelOrder(self, root: TreeNode) -> List[List[int]]:
res = []
q = []
if root:
q.append(root)
while q:
level = []
nextq = []
for root in q:
level.append(root.val)
if root.left:
nextq.append(root.left)
if root.right:
nextq.append(root.right)
res.append(level)
q = nextq
return res
class Solution:
def levelOrder(self, root: TreeNode) -> List[List[int]]:
return [[root.val]] + [a+b for a,b in zip_longest(self.levelOrder(root.left), self.levelOrder(root.right), fillvalue=[])] if root else []
class Solution:
def levelOrder(self, root: TreeNode) -> List[List[int]]:
return(f:=lambda x:x and [[x.val]]+[a+b for a,b in zip_longest(f(x.left),f(x.right),fillvalue=[])]or[])(root)
class Solution:
def levelOrder(self, t: TreeNode) -> List[List[int]]:
return(f:=lambda x:x and[[x.val],*starmap(add,zip_longest(f(x.left),f(x.right),fillvalue=[]))]or[])(t)
#class Solution:
# def levelOrder(self, t: TreeNode) -> List[List[int]]:
# s,p=json.loads(TreeNode.serialize(t)),lambda x:x;return[*takewhile(p,([*filter(p,s[(j:=2**i)-1:2*j-1])]for i in count()))]
test('''
102. Binary Tree Level Order Traversal
Medium
11296
214
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Given the root of a binary tree, return the level order traversal of its nodes' values. (i.e., from left to right, level by level).
Example 1:
Input: root = [3,9,20,null,null,15,7]
Output: [[3],[9,20],[15,7]]
Example 2:
Input: root = [1]
Output: [[1]]
Example 3:
Input: root = []
Output: []
Constraints:
The number of nodes in the tree is in the range [0, 2000].
-1000 <= Node.val <= 1000
''')