A binary tree is named Even-Odd if it meets the following conditions:
- The root of the binary tree is at level index
0
, its children are at level index1
, their children are at level index2
, etc. - For every even-indexed level, all nodes at the level have odd integer values in strictly increasing order (from left to right).
- For every odd-indexed level, all nodes at the level have even integer values in strictly decreasing order (from left to right).
Given the root
of a binary tree, return true
if the binary tree is Even-Odd, otherwise return false
.
Example 1:
Input: root = [1,10,4,3,null,7,9,12,8,6,null,null,2]
Output: true
Explanation: The node values on each level are:
Level 0: [1]
Level 1: [10,4]
Level 2: [3,7,9]
Level 3: [12,8,6,2]
Since levels 0 and 2 are all odd and increasing and levels 1 and 3 are all even and decreasing, the tree is Even-Odd.
Example 2:
Input: root = [5,4,2,3,3,7]
Output: false
Explanation: The node values on each level are:
Level 0: [5]
Level 1: [4,2]
Level 2: [3,3,7]
Node values in level 2 must be in strictly increasing order, so the tree is not Even-Odd.
Example 3:
Input: root = [5,9,1,3,5,7]
Output: false
Explanation: Node values in the level 1 should be even integers.
Constraints:
- The number of nodes in the tree is in the range
[1, pow(10, 5)]
. 1 <= Node.val <= pow(10, 6)
Level Order Traversal:
/**
* Definition for a binary tree node.
* public class TreeNode {
* public var val: Int
* public var left: TreeNode?
* public var right: TreeNode?
* public init() { self.val = 0; self.left = nil; self.right = nil; }
* public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }
* public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {
* self.val = val
* self.left = left
* self.right = right
* }
* }
*/
class Solution {
func isEvenOddTree(_ root: TreeNode?) -> Bool {
guard let root else { return false }
var queue: [TreeNode] = [root]
var isEvenLevel: Bool = true
while !queue.isEmpty {
let count: Int = queue.count
var curr: Int?
for _ in 0 ..< count {
let node = queue.removeFirst()
if (isEvenLevel && node.val % 2 == 0) || (!isEvenLevel && node.val % 2 == 1) {
return false
} else {
if let prev = curr, (isEvenLevel && node.val <= prev) || (!isEvenLevel && node.val >= prev) {
return false
}
curr = node.val
[node.left, node.right].forEach {
guard let next = $0 else { return }
queue.append(next)
}
}
}
isEvenLevel.toggle()
}
return true
}
}