Given the root
node of a binary search tree, return the sum of values of all nodes with value between L
and R
(inclusive).
The binary search tree is guaranteed to have unique values.
Example 1:
Input: root = [10,5,15,3,7,null,18], L = 7, R = 15
Output: 32
Example 2:
Input: root = [10,5,15,3,7,13,18,1,null,6], L = 6, R = 10
Output: 23
Note:
- The number of nodes in the tree is at most
10000
. - The final answer is guaranteed to be less than
2^31
.
O(log[base 2](n)) Time - Recursive:
/**
* Definition for a binary tree node.
* public class TreeNode {
* public var val: Int
* public var left: TreeNode?
* public var right: TreeNode?
* public init(_ val: Int) {
* self.val = val
* self.left = nil
* self.right = nil
* }
* }
*/
class Solution {
func rangeSumBST(_ root: TreeNode?, _ L: Int, _ R: Int) -> Int {
guard let node = root else { return 0 }
switch node.val {
case Int.min..<L:
return rangeSumBST(node.right, L, R)
case R+1...Int.max:
return rangeSumBST(node.left, L, R)
default:
return node.val + rangeSumBST(node.left, L, R) + rangeSumBST(node.right, L, R)
}
}
}