Given a binary tree, you need to compute the length of the diameter of the tree.
The diameter of a binary tree is the length of the longest path between any two nodes in a tree.
This path may or may not pass through the root.
Example:
Given a binary tree
1
/ \
2 3
/ \
4 5
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
Note: The length of path between two nodes is represented by the number of edges between them.
O(n):
/**
* Definition for a binary tree node.
* public class TreeNode {
* public var val: Int
* public var left: TreeNode?
* public var right: TreeNode?
* public init(_ val: Int) {
* self.val = val
* self.left = nil
* self.right = nil
* }
* }
*/
class Solution {
func diameterOfBinaryTree(_ root: TreeNode?) -> Int {
var result = 1
_ = solve(root, &result)
return result-1
}
func solve(_ node: TreeNode?, _ result: inout Int) -> Int {
guard let node = node else { return 0 }
let left = solve(node.left, &result), right = solve(node.right, &result)
result = max(result, left+right+1)
return max(left, right)+1
}
}