Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST.
Example:
Input: The root of a Binary Search Tree like this:
5
/ \
2 13
Output: The root of a Greater Tree like this:
18
/ \
20 13
Note: This question is the same as 1038: https://leetcode.com/problems/binary-search-tree-to-greater-sum-tree/
O(n) Time, O(1) Space - Reverse-In-Order Traversal:
/**
* Definition for a binary tree node.
* public class TreeNode {
* public var val: Int
* public var left: TreeNode?
* public var right: TreeNode?
* public init(_ val: Int) {
* self.val = val
* self.left = nil
* self.right = nil
* }
* }
*/
class Solution {
func convertBST(_ root: TreeNode?) -> TreeNode? {
var sum = 0
traverse(root, &sum)
return root
}
func traverse(_ node: TreeNode?, _ sum: inout Int) {
guard let node = node else { return }
traverse(node.right, &sum)
node.val += sum
sum = node.val
traverse(node.left, &sum)
}
}