Given two integer arrays inorder
and postorder
where inorder
is the inorder traversal of a binary tree and postorder
is the postorder traversal of the same tree, construct and return the binary tree.
Example 1:
Input: inorder = [9,3,15,20,7], postorder = [9,15,7,20,3]
Output: [3,9,20,null,null,15,7]
Example 2:
Input: inorder = [-1], postorder = [-1]
Output: [-1]
Constraints:
1 <= inorder.length <= 3000
postorder.length == inorder.length
-3000 <= inorder[i], postorder[i] <= 3000
inorder
andpostorder
consist of unique values.- Each value of
postorder
also appears ininorder
. inorder
is guaranteed to be the inorder traversal of the tree.postorder
is guaranteed to be the postorder traversal of the tree.
/**
* Definition for a binary tree node.
* public class TreeNode {
* public var val: Int
* public var left: TreeNode?
* public var right: TreeNode?
* public init() { self.val = 0; self.left = nil; self.right = nil; }
* public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }
* public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {
* self.val = val
* self.left = left
* self.right = right
* }
* }
*/
class Solution {
func buildTree(_ inorder: [Int], _ postorder: [Int]) -> TreeNode? {
build(
inorder,
postorder,
ClosedRange(uncheckedBounds: (0, inorder.count - 1)),
ClosedRange(uncheckedBounds: (0, postorder.count - 1))
)
}
func build(_ inorder: [Int], _ postorder: [Int], _ iRange: ClosedRange<Int>, _ pRange: ClosedRange<Int>) -> TreeNode? {
if pRange.lowerBound <= pRange.upperBound {
let value: Int = postorder[pRange.upperBound]
if let nodeIndex = inorder.firstIndex(where: { $0 == value }) {
let numLeftNodes: Int = nodeIndex - iRange.lowerBound
let node: TreeNode = TreeNode(value)
node.left = build(
inorder,
postorder,
ClosedRange(uncheckedBounds: (iRange.lowerBound, nodeIndex - 1)),
ClosedRange(uncheckedBounds: (pRange.lowerBound, pRange.lowerBound + numLeftNodes - 1))
)
node.right = build(
inorder,
postorder,
ClosedRange(uncheckedBounds: (nodeIndex + 1, iRange.upperBound)),
ClosedRange(uncheckedBounds: (pRange.lowerBound + numLeftNodes, pRange.upperBound - 1))
)
return node
} else {
fatalError()
}
} else {
return nil
}
}
}