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use condition StringMatch to preform startsWith and contains on a String.
StringMatch
String
StringMatch only supports static values.
May also be able to StringSplit($.value, $.searchTerm) to accomplish these.
StringSplit($.value, $.searchTerm)
ArrayLength(StringSplit(..)) > 2
ArrayLength(StringSplit(..)) > 2 && arr[0] === ""
The text was updated successfully, but these errors were encountered:
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use condition
StringMatch
to preform startsWith and contains on aString
.StringMatch only supports static values.
May also be able to
StringSplit($.value, $.searchTerm)
to accomplish these.ArrayLength(StringSplit(..)) > 2
=> contains == true.ArrayLength(StringSplit(..)) > 2 && arr[0] === ""
starts with == trueThe text was updated successfully, but these errors were encountered: