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This requires taking into account the symbol type, because the constructor only resolves to a short symbol name (e.g. QString, not QString::QString) which we a automatically treat as a class and show documentation for the entire class. We know that the symbol is in fact constructor, it is just not take into account when building the full symbol name.
The text was updated successfully, but these errors were encountered:
This requires taking into account the symbol type, because the constructor only resolves to a short symbol name (e.g.
QString
, notQString::QString
) which we a automatically treat as a class and show documentation for the entire class. We know that the symbol is in fact constructor, it is just not take into account when building the full symbol name.The text was updated successfully, but these errors were encountered: