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LightOj 1075.cpp
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LightOj 1075.cpp
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/*
Problem name : 1075 - Finding Routes
Algorithm : Not Sure Yet
Contest/Practice : Off Line Practice
Source : Light Oj
Comment : Whenever you start to believe yourself, people also start to believe in you
Date : 21-Dec-14
*/
#include<bits/stdc++.h>
#define pause system("pause");
#define FOR(s,e,inc) for(int i=s;i<=e;i+=inc)
#define mod 1000000007
#define inf 1<<30
#define pb push_back
#define ppb pop_back
#define mp make_pair
#define F first
#define S second
#define sz(x) ((int)x.size())
#define sqr(x) ( (x)* (x) )
#define eps 1e-9
#define gcd(x,y) __gcd(x,y)
#define lcm(x,y) (x/gcd(x,y))*y
#define on(x,w) x|(1<<w)
#define check(x,w) (x&(1<<w))
#define all(x) (x).begin(),(x).end()
#define pf printf
#define pi acos(-1.0)
#define reset(x,v) memset(x,v,sizeof(x));
#define AND &&
#define OR ||
typedef long long ll;
typedef unsigned long long llu;
using namespace std;
template<class T>
inline T mod_v(T num)
{
if(num>=0)
return num%mod;
else
return (num%mod+mod)%mod;
}
template<class T>
T fast_pow(T n , T p)
{
if(p==0) return 1;
if(p%2)
{
T g=mod_v ( mod_v(n) * mod_v(fast_pow(n,p-1)) );
return g;
}
else
{
T g=fast_pow(n,p/2);
g=mod_v( mod_v(g) * mod_v(g) ) ;
return g;
}
}
template<class T>
inline T modInverse(T n)
{
return fast_pow(n,mod-2);
}
template<class T>
inline void debug(string S1,T S2,string S3)
{
cout<<S1<<S2<<S3;
}
template<class T>
inline T in()
{
register char c=0;
register T num=0;
bool n=false;
while(c<33)c=getchar();
while(c>33){
if(c=='-')
n=true;
else num=num*10+c-'0';
c=getchar();
}
return n?-num:num;
}
#ifndef ONLINE_JUDGE
# define p(x) cout<<x<<endl;
#else if
# define p(x) 0;
#endif
/*...... ! Code start from here ! ......*/
int main()
{
int t,tcase=1,s;
int mark[340];
int cnt[340];
string s1,s2;
t=in<int>();
while(t--)
{
scanf("%d",&s);
reset(mark,0);
reset(cnt,0);
map<string,int>name1;
map<int,string>name2;
int c=1,nw;
for(int i=1;i<s;i++)
{
cin>>s1>>s2;
if(!name1[s1])
{
name1[s1]=c;
name2[c]=s1;
c++;
}
if(!name1[s2])
{
name1[s2]=c;
name2[c]=s2;
c++;
}
mark[name1[s1]]=name1[s2];
cnt[name1[s1]]++;
cnt[name1[s2]]++;
}
for(int i=1;i<c;i++)
if(mark[i] && cnt[i]==1)
{
nw=i;
break;
}
printf("Case %d:\n",tcase++);
for(int i=1;i<=s;i++)
{
cout<<name2[nw]<<"\n";
nw=mark[name1[name2[nw] ]];
}
printf("\n");
}
return 0;
}