listsstringsdictionaries.py

1.
Question 1

The format_address function separates out parts of the address string into new strings: house_number and street_name, and returns: "house number X on street named Y". The format of the input string is: numeric house number, followed by the street name which may contain numbers, but never by themselves, and could be several words long. For example, "123 Main Street", "1001 1st Ave", or "55 North Center Drive". Fill in the gaps to complete this function.

1 / 1 point


def format_address(address_string):
  # Declare variables
  house_number = 0
  street_name = []
  # Separate the address string into parts
  address = address_string.split()
  # Traverse through the address parts
  for item in address:


Correct
Great work! You've remembered how to work with string
methods and use variables for formatting output

2.
Question 2
The highlight_word function changes the given word in a sentence to its upper-case version. For example, highlight_word("Have a nice day", "nice") returns "Have a NICE day". Can you write this function in just one line?

1 / 1 point


def highlight_word(sentence, word):
	return(sentence.replace(word,word.upper()))


print(highlight_word("Have a nice day", "nice"))
print(highlight_word("Shhh, don't be so loud!", "loud"))
print(highlight_word("Automating with Python is fun", "fun"))


Correct
Nice job! You're mastering your string skills!



3.
Question 3
A professor with two assistants, Jamie and Drew, wants an attendance list of the students, in the order that they arrived in the classroom. Drew was the first one to note which students arrived, and then Jamie took over. After the class, they each entered their lists into the computer and emailed them to the professor, who needs to combine them into one, in the order of each student's arrival. Jamie emailed a follow-up, saying that her list is in reverse order. Complete the steps to combine them into one list as follows: the contents of Drew's list, followed by Jamie's list in reverse order, to get an accurate list of the students as they arrived.

1 / 1 point


def combine_lists(list1, list2):
  # Generate a new list containing the elements of list2
  # Followed by the elements of list1 in reverse order
  new_list = list2
  for i in reversed(range(len(list1))):
    new_list.append(list1[i])
  return new_list
  
	
Jamies_list = ["Alice", "Cindy", "Bobby", "Jan", "Peter"]


Correct
Excellent! You're using the list functions correctly, and it
shows!




4.
Question 4
Use a list comprehension to create a list of squared numbers (n*n). The function receives the variables start and end, and returns a list of squares of consecutive numbers between start and end inclusively.
For example, squares(2, 3) should return [4, 9].

1 / 1 point



def squares(start, end):
	return [(x*x) for x in range(start,end+1)]

print(squares(2, 3)) # Should be [4, 9]
print(squares(1, 5)) # Should be [1, 4, 9, 16, 25]
print(squares(0, 10)) # Should be [0, 1, 4, 9, 16, 25, 36, 49, 64, 81, 100]


Correct
Right on! You're making the correct calculation, and using
the correct range.



5.
Question 5
Complete the code to iterate through the keys and values of the car_prices dictionary, printing out some information about each one.

1 / 1 point


def car_listing(car_prices):
  result = ""
  for key,value in car_prices.items():
    result += "{} costs {} dollars".format(key,value) + "\n"
  return result

print(car_listing({"Kia Soul":19000, "Lamborghini Diablo":55000, "Ford Fiesta":13000, "Toyota Prius":24000}))


Correct
You got it! You've correctly gone through the items of the
dictionary!



6.
Question 6
Taylor and Rory are hosting a party. They sent out invitations, and each one collected responses into dictionaries, with names of their friends and how many guests each friend is bringing. Each dictionary is a partial list, but Rory's list has more current information about the number of guests. Fill in the blanks to combine both dictionaries into one, with each friend listed only once, and the number of guests from Rory's dictionary taking precedence, if a name is included in both dictionaries. Then print the resulting dictionary.

1 / 1 point


from copy import deepcopy
def combine_guests(guests1, guests2):
  # Combine both dictionaries into one, with each key listed 
  # only once, and the value from guests1 taking precedence
  backup = deepcopy(guests1)
  guests1.update(guests2)
  for guest in guests1:
      if guest in backup:
        guests1[guest] = backup[guest]
  return guests1


Correct
You nailed it! You've figured out the best way to call the
update() method, to have the values from the first
dictionary added or updated over the second dictionary.



7.
Question 7
Use a dictionary to count the frequency of letters in the input string. Only letters should be counted, not blank spaces, numbers, or punctuation. Upper case should be considered the same as lower case. For example, count_letters("This is a sentence.") should return {'t': 2, 'h': 1, 'i': 2, 's': 3, 'a': 1, 'e': 3, 'n': 2, 'c': 1}.

1 / 1 point


def count_letters(text):
    elements = text.replace(" ","").lower()
    result = {}
    for letter in elements:
        if letter.isalpha():            
            if letter not in result:
                result[letter] = 1
            else:
                result[letter] +=1
    return result   


Correct
Woohoo! You've remembered the relevant string commands, and
how to work with dictionaries.


8.
Question 8
What do the following commands return when animal = "Hippopotamus"?


>>> print(animal[3:6])
>>> print(animal[-5])
>>> print(animal[10:])

1 / 1 point


pop, t, us

Correct
You got it! When both parts of a string index range are included, the substring starts at first index and ends at second index minus 1. When the index is negative, the character is counted from the end of the string. When the second index is omitted, it goes until the end of the string.


9.
Question 9
What does the list "colors" contain after these commands are executed?

123
colors = ["red", "white", "blue"]
colors.insert(2, "yellow")

1 / 1 point

['red', 'white', 'yellow', 'blue']

Correct
Right on! The insert command inserts the new element into the list at the specified index, shifting the other elements over afterwards.



10.
Question 10
What do the following commands return?

123
host_addresses = {"router": "192.168.1.1", "localhost": "127.0.0.1", "google": "8.8.8.8"}
host_addresses.keys()

1 / 1 point


['router', 'localhost', 'google']

Correct
You got it! In dictionaries, the keys() command returns a list of just the keys, which is what this is